廣東北電的筆試題
1.漢譯英
北電網(wǎng)絡的開發(fā)者計劃使來自于不同組織的開發(fā)者,能夠在北電網(wǎng)絡的'平臺上開發(fā)圓滿的補充業(yè)務。北電網(wǎng)絡符合工業(yè)標準的開放接口,為補充業(yè)務的開展引入了無數(shù)商機,開發(fā)者計劃為不同層面的開發(fā)者提供不同等級的資格,資格的劃分還考慮到以下因素:補充業(yè)務與北電網(wǎng)絡平臺的集合程度,開發(fā)者團體與北電網(wǎng)絡的合作關系,等等。
答:呵呵。這個這個基本上還是不現(xiàn)丑了吧。
2.編程
將整數(shù)轉(zhuǎn)換成字符串:void itoa(int,char);
例如itoa(-123,s[])則s=“-123”;
答:
char* itoa(int value, char* string)
{
char tmp[33];
char* tp = tmp;
int i;
unsigned v;
char* sp;
// 將值轉(zhuǎn)為正值
if (value < 0)
v = -value;
else
v = (unsigned)value;
// 將數(shù)轉(zhuǎn)換為字符放在數(shù)組tmp中
while (v)
{
i = v % 10;
v = v / 10;
*tp++ = i+'0';
}
// 將tmp里的字符填入string指針里,并加上負號(如果有)
sp = string;
if (value < 0)
*sp++ = '-';
while (tp > tmp)
*sp++ = *–tp;
*sp = 0;
return string;
}
英文筆試題
1. Tranlation (Mandatory)
CDMA venders have worked hard to give CDMA roaming capabilities via the development of RUIM-essentially, a SIM card for CDMA handsets currently being deployed in China for new CDMA operator China Unicom. Korean cellco KTF demonstrated earlier this year the ability to roam between GSM and CDMA using such cards.However,only the card containing the user’s service data can roam-not the CDMA handset or the user’s number (except via call forwarding).
2. Programming (Mandatory)
Linked list
a. Implement a linked list for integers,which supports the insertafter (insert a node after a specified node) and removeafter (remove the node after a specified node) methods;
b. Implement a method to sort the linked list to descending order.
3. Debugging (Mandatory)
a. For each of the following recursive methods,enter Y in the answer box if themethod terminaters (assume i=5), Otherwise enter N.
static int f(int i){
return f(i-1)*f(i-1);
}
Ansewr:
static int f(int i){
if(i==0){return 1;}
else {return f(i-1)*f(i-1);}
}
Ansewr:
static int f(int i){
if(i==0){return 1;}
else {return f(i-1)*f(i-2);}
}
Ansewr:
b. There are two errors in the following JAVA program:
static void g(int i){
if(i==1){return;}
if(i%2==0){g(i/2);return;}
else {g(3*i);return;}
}
please correct them to make sure we can get the printed-out result as below:
3 10 5 16 8 4 2 1
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