GRE數(shù)學(xué)滿分是幾乎所有中國考生的既定目標(biāo)，而想要確保自己不會(huì)在考試中因?yàn)橐粫r(shí)粗心而丟失分?jǐn)?shù)，提前了解可能出現(xiàn)的考點(diǎn)陷阱就是必須做好的準(zhǔn)備工作了。下面是小編為大家整理收集的關(guān)于12月4日數(shù)學(xué)機(jī)經(jīng)的相關(guān)內(nèi)容，歡迎大家的閱讀。

　　題目

　　1. If k is an integer and 121 < k^2 < 225,then k can have at most how many values?

　　A. 3

　　B. 4

　　C. 5

　　D. 6

　　E. 7

　　答案：D.

　　解析：k可以是12,13,14,-12,-13,-14.

　　2. Runner A ran 4/5 kilometer and Runner B ran 800 meters.

　　Quantity A: The distance that A ran

　　Quantity B: The distance that B ran

　　A. Quantity A is greater.

　　B. Quantity B is greater.

　　C. The two quantities are equal.

　　D. The relationship cannot be determined from the information given.

　　答案：C

　　解析：Quantity A=(4/5)*1000=800=Quantity B。

　　3. x < y < z,

　　Quantity A: (x + y + z)/3

　　Quantity B: y

　　A. Quantity A is greater.

　　B. Quantity B is greater.

　　C. The two quantities are equal.

　　D. The relationship cannot be determined from the information given.

　　答案：D

　　解析：已知條件太少，AB大小都可以根據(jù)不同數(shù)據(jù)列出可能答案，因此無法判斷準(zhǔn)確唯一解，選D。

　　4. A reading list for a humanities course consists of 10 books, of which 4 are biographies and the rest are novels. Each student is required to read a selection of 4 books from the list, including 2 or more biographies. How many selections of 4 books satisfy the requirements?

　　A. 90

　　B. 115

　　C. 130

　　D. 144

　　E. 195

　　答案：D

　　解析：10本書中，4本biographies，6本novel�，F(xiàn)在biographies要選2本以上。

　　思路1：正面解法

　　所以可能情形有bio選2本(配nov選2)+bio選3本(配nov選1本)+bio選4本(配nov選0本)。

　　即(C4取2乘C6取2)+(C4取3乘C6取1)+(C4取4乘C6取0)=115

　　思路2：反向解法

　　用全部扣除bio選0本(配nov選4)再扣bio選1本(配nov選3)

　　利用C10取4-C4取0*C6取4-C4取1*C6取3 = 210 - 15 - 80 = 115

　　5. In a graduating class of 236 students, 142 took algebra and 121 took chemistry. What is the greatest possible number of students that could have taken both algebra and chemistry?

　　答案：121

　　解析：可能不少人會(huì)用142+121-236=27的思路來解題，但問題是least possible number，同時(shí)也沒有表明只能選兩門課，因此有可能還有其他課可選，因此正確答案是眼前兩個(gè)交集的最大數(shù)，也就是142和121取最小數(shù)，121個(gè)學(xué)chemistry的都選了algebra。所以為121。